BlueSky stats for Jason Dogwood 💙 🏳️‍🌈 🌱

Jason Dogwood 💙 🏳️‍🌈 🌱

@jasondogwood.bsky.social

42K followers 10K following 4,048 posts

On Bluesky since September 2023

10.0

Wickedly gay 🏳️‍🌈. Woke AF ☮️ Vegan 🌱 Trans rights are human rights 🏳️‍⚧️ I don’t follow back accounts that don't post. I TELL THE TRUTH, CARE TO LISTEN? #FightTheOligarchs #Vegan #QueerAF #TransRights

Jason Dogwood 💙 🏳️‍🌈 🌱's Profile Stats

🗣️ Audience: Jason Dogwood 💙 🏳️‍🌈 🌱 is a Bluesky celebrity, ranking in the top 0.1% of all users on Bluesky by number of followers.

📅 Join date: Jason Dogwood 💙 🏳️‍🌈 🌱 joined Bluesky earlier than 96% of users, making them one of the first wave of members.

🎁 Starter packs: Jason Dogwood 💙 🏳️‍🌈 🌱 created 5 starter packs. Jason Dogwood 💙 🏳️‍🌈 🌱 is listed in 234 starter packs.

Recent activity

💬 Last post about 11 hours ago, posted 47 times in the last 7 days.

💙 Last like about 6 hours ago, liked 451 posts in the last 7 days.

🔗 Last follow about 8 hours ago, followed 43 users in the last 7 days.

📈 Received 4,967 likes and 1,829 reposts in the last 7 days.

🏆 Achievements

Jason Dogwood 💙 🏳️‍🌈 🌱 is currently not in the Most Followers Added (24h) list. The best ranking in the past 30 days was 291st, achieved on Oct 22nd.
Jason Dogwood 💙 🏳️‍🌈 🌱 is currently not in the Most Engaging Users list. The best ranking in the past 30 days was 468th, achieved on Oct 27th.

Share these stats with your followers!

Jason Dogwood 💙 🏳️‍🌈 🌱 Bluesky Followers over time

Follower prediction

Jason Dogwood 💙 🏳️‍🌈 🌱 gains approximately 22 followers per day. At this rate Jason Dogwood 💙 🏳️‍🌈 🌱 is expected to reach 43K followers in 18 days and 50K followers in 11 months.

Jason Dogwood 💙 🏳️‍🌈 🌱's CloudRank

The CloudRank is a score from 0 to 10 based on your followers and your activity in the last week.

Based on the number of followers and how influential those followers themselves are, we calculate the popularity score: 10.0
Based on your 4,967 likes and 1,829 reposts in the last 7 days, your reach score is 10.0.
The CloudRank is the average of these two scores.